News & Events


Krushna Deshmukh, CMAT AIR 1, JBIMS

krishna I want to thank the entire ELC team for making it possible for me to crack CMAT exam and join one of the top Business Schools. ELC test series helped me understanding exam pattern and detailed solutions given at the end helped me understanding concepts better. I am impressed by the quality of inputs given to help improve my scores as well as the professional behavior displayed by the ELC staff. The staff at ELC is very committed and they take a personal interest to help you. Tips and tricks given by Sagar sir helped in saving crucial time in exam. With Sagar Sir’s constant motivation and guidance, I was able to land in my dream college. On the whole, I highly recommend the services offered by ELC eduation.

Rupesh Ezuthachen, JBIMS

rupesh To put it in a nutshell, there have been many turning points in my life but ELC was the most significant one. It landed me in JBIMS, one of the most prestigious institutions in the country. I was working in Voltas Ltd and had a hectic work schedule. I was not able to dedicate enough time for studies and was not well prepared for the CET exam.

But, the 2-day workshop conducted by Mr.Sagar Nikam re-energized me to take up the preparations more seriously. He covered the different topics in his unique way with excellent shortcut techniques which increased my speed & I was able to solve more number of questions in actual CET paper. The workshop was then complimented with the Test Series which had a very user friendly interface which helped me in devising a strategy, reviewing my results, identifying my strong & weak areas and tracking my performance against the other students. My advice to all the CET aspirants- “ Focus on speed with accuracy”

I would highly recommend everyone to join the ELC workshop & test series because it will definitely give you an edge in your CET preparation.

My best wishes to the ELC team for all their future endeavou

Pradip Ekhande, JBIMS

pradipekhande "ELC - Source of knowledge and motivation ELC as an entrance class, not only offers you the tips and tricks required for cracking the MBA entrance but it also becomes an source of motivation for getting into one of the Ivy league college. Sagar sir always made us believe that, getting into any top college is easy. The only thing we required to get into one was right approach, dedication and confidence in ourselves. To motivate students, mentors at ELC organized various guest lectures by persons associated with top level institutes. Sagar sir also used to inspire us by telling about the life at JBIMS and how our life can change by going for an MBA from Ivy league college. This motivation by Sir worked for me most of the times and it is because of his motivation, today I am a member of JBIMS family and enjoying my life here. To summarize it won’t be wrong to say that major chunk of the credit for my success goes to Sagar sir and Madhura mam. It was their proper guidance and training which helped me sharpen my aptitude and comprehension skills ,which eventually are very crucial for cracking any of the MBA entrance exam. Cheers !"

MBA CET is Back!

CET is a race against time. You can outperform your competition only when your methods of solving questions are different from others. This document will give you an approach of the topper to solve the questions in MBA CET. To learn more such methods and increase your score atleast by 40, you have an opportunity to attend our 2 daysworkshop to be conducted in your city.

MBA CET Pattern

Section-wise weightage

How MBA CET is different from other exams:

  • 30 questions on visual reasoning
  • More than 50% reasoning (Logical + visual)
  • No negative marking
  • 45 seconds per question

Generally students feel that once you prepare for CAT, you will find CET very easy. That’s true. But solving 200 questions in 150 minutes is the real challenge. We suggest you to take our online mock CET on or take any mock CET from any institute and see your score. Compare the score with the following cutoffs of different colleges as per last 3 CETs.

Institute Cut off Score (Out of 200)
Jamnalal Bajaj (JBIMS) 150
Sydenham 140
K. J. Somaiya 135
Welingkar 132
SIES 128

  • If your score is less than the cut off score of your dream institute, its time to take guidance from the expert. See below some of the questions asked in CET, they have been explained using Basic methods and further with ELC’s Speed Techniques.

Some of our sample tricks for MBA CET

Toppers Tricks for Pie Charts Questions:

Directions (Questions 1 to 3) :

Study the following graph carefully and answer the questions given below:

Distribution of candidates who were enrolled for MBA entrance exam and the candidates (out of those enrolled) who passed the exam in different institutes P, Q, R, S, T, U, V.

Q. 1 What percentage of candidates passed the Exam from institute T out of the total number of candidates enrolled from the same institute?

(a) 67.5%
(b) 62.5%
(c) 65%
(d) 60%

Basic Method:

Number of students passed from institute T = 9% of 3914 = 352
Number of students enrolled from institute T = 8% of 6524 = 523
Required % = = 67.3 ≈ 67.5

ELC Method

Find the approximate ratio of the total students enrolled to the total students passed.
6524 : 3914 ≈ 5 : 3 (We will call this ratio as the master ratio)
Equivalent number enrolled = 8 × 5 = 40
Equivalent number passed = 9 × 3 = 27
Required % = 67.5

Q. 2 What is the closest ratio of candidates passed to the candidates enrolled from institute P?

(a) 7 : 11
(b) 1 : 2
(c) 3 : 7
(d) 9 : 16

Basic Method:

Number of students passed from institute P = 18% of 3914 = = 704
Number of students enrolled from institute T = 22% of 6524 = = 1435
Required ratio = 704:1435 ≈ 1:2

ELC Method

Master ratio as found in Q. 1 is 5:3
Equivalent number enrolled = 22 × 5 = 110
Equivalent number enrolled = 18 × 3 = 54
Required ratio = 54 : 110 ≈ 1:2

Q. 3 What is the percentage of candidates passed to the candidates enrolled for institutes Q and R together?

(a) 68%
(b) 80%
(c) 72%
(d) 65%

Basic Method:

Candidates passed from Q and R together is 17% + 13% = 30% of 3914 = 1174
Candidates enrolled from Q and R together is 15% + 10% = 25% of 6524 = 1631
Required % = = 72%

ELC Method:

Ratio of the % of Q and R passed to enrolled = 30 : 25 = 6:5
Multiply it with the master ratio of passed to enrolled.
Required ratio = (6:5) × (3:5) = 18:25
Required % = = 72%

Topper’s Tricks for Tracing Sequential Output Questions

Directions for questions 4 to 5: Given an input line the machine arranges the words and numbers in steps in a systematic manner as illustrated below:

  • Input : Maken pledges help to Yuvraj in cancer fight
  • Step 1: cancer fight help to Yuvraj in Maken pledges
  • Step 2: cancer fight Yuvraj in help to Maken pledges
  • Step 3: pledges Maken to help in Yuvraj fight cancer
  • Step 4: in Yuvraj fight cancer pledges Maken to help
  • Step 5: Yuvraj in cancer fight Maken pledges help to
  • Step 6: to in cancer Maken fight pledges help Yuvraj

Step 6 is the last step and the output in step 6 is the final output.

As per the rules followed in the above steps, find out in each of the following questions the appropriate steps for the given input.

Q. 4 Which step will be the last step for the following input?

Ramleela has joined hundred crore club first week
(a) Ramleela hundred club first week has joined crore
(b) club hundred first Ramleela week has joined crore
(c) hundred club first Ramleela week has joined crore
(d) week hundred club first Ramleela has joined crore
(e) hundred club Ramleela first week has joined crore

Basic Method:

Right the all the steps for the given input.
Certainly time consuming.

ELC Method:

  • Go to the options, see the place where maximum options have different words.
  • First word is different in maximum options.
  • See the given directions, see the first word in the output step.
  • The word is ‘to’ this word was at fourth position in the input.
  • So we can say that the fourth word in the input becomes first word in the output.
  • The fourth word in this question input is ‘hundred’
  • This should be the first word in the output.
  • So options a,b, and d gets eliminated.
  • Now see the difference between options c and e.
  • Third word is different in both the options.
  • Now do the process for the third word in the output as done above.
  • As ‘cancer’ was the second last word in the input, the second last word in the question – ‘first’ should be the third word in the output.
  • Hence c is the answer.

Here instead of checking the position of all the 8 words we checked the same for only 2 words and saved our time.

Q. 5 If Step 5 of an input is

Four old actresses are making comeback this year
Which of the following will definitely be input?
(a) making comeback this year four old are actresses
(b) making comeback this year four old actresses are
(c) making comeback this year four actresses are old
(d) making comeback this four old actresses are year
(e) making comeback this year four old are actresses

Basic Method:

Backtracking each word from Step 5 to the input as per the logic in the direction example.
Time consuming process.

ELC Method

  • See the place in the option sentences, which has different words in the maximum options.
  • The last word is different in maximum options.
  • Hence see the last word in the input of direction example was ‘fight’.
  • This word was forth word in step 5.
  • The fourth word in the step 5 of question sentence is ‘are’
  • Which should be the last word in the input.
  • This is happening in case of option b and hence b is the answer.

Instead of tracking 8 words, we tracked only one word and got the answer!

Topper’s Tricks for Visual Reasoning Questions

Q. 6 The five figures given as problem figures follow certain logic. Understand the logic and find the sixth figure in the sequence.

Basic Method:

  • Firstly, understand the logic.
  • From first to second figure, two figures on the right hand are interchanging their places.
  • The remaining three symbols are rotating clockwise, while doing so the center symbol is replaced by a new symbol.
  • From second to the third figure, two figures on the left hand are interchanging their places.
  • The remaining three symbols are rotating clockwise, while doing so the center symbol is replaced by a new symbol.
  • The logics mentioned above are occurring alternately.
  • Tracing this logic, the answer should be b.

ELC Method

  • Rather than tracking the whole logic take any one symbol and track its positions in consecutive figures.
  • Let us take symbol ‘C’. It is moving one place up, one place down in alternate figures.
  • It should be at upper left corner in sixth figure.
  • Using this, options c and d get eliminated.
  • Now see that the new symbol is getting added at the center in each figure.
  • Options b and e use the symbol ‘o’ which is not new.
  • Hence a is the answer.


  • Before looking at the problem figure, see all the options.
  • Locate the place where maximum options have different symbols.
  • You can see, left bottom corner has different symbol in different options.
  • Now track the left bottom symbol in problem figures.
  • ‘C’ is coming alternately and in alternate figures, the symbol at the center in the previous figure is coming.
  • Using this logic, symbol at the center in the fifth figure was ‘T’.
  • It should be there at the left bottom corner, this is happening in option ‘b’ only and hence b is the answer.

Topper’s Tricks for Numerical Data Tables Questions

Directions for questions 7 to 8: The following table shows the number of boys and girls of different schools that have participated in a scholarship test over years.

School Year A B D
Boys Girls Boys Girls Boys Girls
2007 300 310 320 314 289. 312
2008 305 293 316 315 278 310
2009 311 297 325 320 279 321
2010 314 310 322 316 283 315
2011 313 298 312 324 288 319
2012 321 316 331 315 293 314

Q. 7 The difference between number of girls from school C and D including all the years is:

(a) 13
(b) 14
(c) 12
(d) None of these

Basic Method:

Add the number of girls from C in given years.
314 + 315 + 320 +316 + 324 + 315 = 1904
Add the number of girls from D in given years.
312 + 310 + 321 + 315 + 319 + 314 = 1891.
Required difference = 1904 – 1891 = 13

ELC Method:

  • Find the difference between the number of girls separately for each year and then ad these differences only.
  • Number of girls in C in 2007 = 314, the same of D = 312
  • Difference = 314 – 312 = 2
  • Next difference is 315 – 310 = 5
  • Ad this to the previous difference.
  • So accumulated difference = 2 + 5 = 7
  • Continuing with this the answer is = 2 + 5 – 1 +1 + 5 + 1 = 13
  • Here we dealt with only single digit small numbers and hence got the answer fast.

Q. 8 What is the average number of girls per year for school A in the given period?

(a) 300
(b) 302
(c) 304
(d) 306

Basic Method:

Add all the number of girls in the given period and then divide by number of years.
Total number of girls in the given period =
310+293+297+310+298+316 = 1824
= 304

ELC Method:

  • Have a look at all the numbers whose average you have to find. What do they tell you? That the average will be around 300. So consider 300 as our reference point.
  • See each number. See how much greater or lesser the number is compared to 300.
    i.e. first number 310. It is +10.
  • Second number is 293. It is -7.
  • Combined effect of +10 and -7 is +3.
  • Next is 297. It is -3. Combined effect till now is +3 -3 = 0.
  • Doing so for all the numbers, the combined effect becomes,
    +10 – 7 = 3 -3 = 0 +10 = 10 – 2 = 8 + 16 = 24.
  • So the average will be 300 + = 304

Here we dealt with small numbers and hence got the answer fast.

Q 9 Which year has shown maximum % of boys to girls in school A?

(a) 2008
(b) 2009
(c) 2011
(d) 2012

Basic Method

    Find the required % in each year.
    Year 2008: = 104
    Year 2009: = 104.7
    Year 2011: = 105.4
    Year 2012: = 101.5
    The highest value is 105.4.
    Hence answer is c.
    All these calculations are time consuming.

ELC Method

We can suggest various methods to compare fractions. Particularly in this case, since all the numbers are very close to each other, find the difference between the numerator and the denominator for each fraction.

  • Year 2008: 305 – 293 = 12
  • Year 2009: 311 – 297 = 14
  • Year 2011: 313 – 298 = 15
  • Year 2012: 321 – 316 = 5
  • Since in year 2011 the difference between the numerator and the denominator is highest, this fraction will have the highest value.
  • Hence ans is c.

Topper’s Tricks for Simple Interest Questions

Q. 10 The simple interest on a certain sum of money at the rate of 5% p.a. for 8 years is Rs. 840. At what rate of interest the same amount of interest can be received on the same sum after 5 years?

(a) 8
(b) 6
(c) 7
(d) 9

Basic Method:

Using the formula for Simple Interest (SI)
SI =
840 =
P =
Solving, p = 2100.
To find the rate of interest in the second condition, again using the same formula,
SI =
840 =
∴ r =
Solving, r = 8

ELC Method

  • In both the cases, SI and P are same.
  • Hence the percentage getting added on P is also same.
  • In first case, % getting added = 8 × 5 = 40
  • Hence % getting added in second case = 40
  • This should be added in 5 years.
  • Hence each year % added = = 8.

Q. 11 The difference in compound interest and simple interest on a certain amount at 8 % per annum at the end of the second year is Rs. 32. What is the principal amount?

(a) 5000
(b) 3000
(c) 4000
(d) 6000

Basic Method:

CI = A – P
= P - P
=P - P
=P(1.08)2 – P
=P(1.1664) – P
SI = = = 0.16P
CI – SI = 0.1664P – 0.16P = 0.0064P = 32
P = = 5000.

ELC Method:

After 1 year, SI and CI are same.
The difference starts in 2nd year, because in CI there is interest on 1st year’s interest.
Let 1st year’s interest be I.
Hence 8% of I = 32
I = = 400
This is interest on P at 8%
∴8% of P = 400
P = = 5000.

You will get to learn hundreds of such tricks in ELC’s 2 day workshops which will be conducted in 7 cities in Maharashtra.

Workshop Details

  • Unique Speed Techniques by the Topper on all the important topics for MBA CET 2014
  • Target to increase your score by 40
  • 2 days (Saturday & Sunday), 10 am to 5 pm every day
  • 10 take home mock CET Tests with detail solutions
  • Fees: Rs. 1000/-
  • Attend first 1 hour free, if you find it’s worth, then pay
  • Topics covered: Visual Reasoning (6 types), Tracing Sequential Output (5 types), Data Interpretation (Bar, Line, Tables, Pie Charts), Syllogisms (All types), Alpha Numeric Sequence, All topics in Quantitative Aptitude, Critical Reasoning, Cloze Test, Reading Comprehension, Probably True-False, Statement – Assumption,Conclusion, Inference, Strengthening-Weakening Arguments, Cause-Effect,Statement Course of Action, etc.

Online Test Series Details

  • 10 online Tests as per the actual CET pattern
  • All tests simulating actual CETs considering last 5 years pattern
  • All tests with detailed solutions and graphical analysis
  • Fees: Rs. 800/-
  • Take free online mock CET on

Combo Pack

  • Workshop + Online Test Series @ Rs 1800 / but Rs. 1500/-

Registration Process

  • Visit and fill free registration form
  • Or sms : <Your Name_City Name> on 8149466354 or 9860650606

About ELC

Excellence Learning Centre Pvt. Ltd. was started as the final year project of MBA CET Topper and JBIMS student of 2008-10 batch Mr. SagarNikam. With the huge success of his first batch students, he rejected the lucrative campus placement offer and started his journey towards teaching the students his secrets of success – his unique speed techniques. Since then every year ELC is getting best results in all the cities it operates in.


Sagar Nikam
Director, ELC Pvt. Ltd.

University Topper in SE, TE and BE
MBA CET State Topper, CAT 99.85%ler, CMAT AIR 43, N.T.S. Scholar

Madhura Shelar
Director, ELC Pvt. Ltd.

B.E.( KKWIEER), M.B.A. (Indira Inst.)
University Topper in TE and BE
Worked for ABB for 1 year and E-clerx for 1.5 years


The Biggest Workshop for MBA CET

Contact Details

Address: ELC, Above SBI, Opp KFC, Near BYK College, Off College Road, Nashik – 422005.
Ph: 8459201314, 9860650606